(2g-3)(2g^2+g-4)=0

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Solution for (2g-3)(2g^2+g-4)=0 equation: 


Simplifying
(2g + -3)(2g2 + g + -4) = 0

Reorder the terms:
(-3 + 2g)(2g2 + g + -4) = 0

Reorder the terms:
(-3 + 2g)(-4 + g + 2g2) = 0

Multiply (-3 + 2g) * (-4 + g + 2g2)
(-3(-4 + g + 2g2) + 2g * (-4 + g + 2g2)) = 0
((-4 * -3 + g * -3 + 2g2 * -3) + 2g * (-4 + g + 2g2)) = 0
((12 + -3g + -6g2) + 2g * (-4 + g + 2g2)) = 0
(12 + -3g + -6g2 + (-4 * 2g + g * 2g + 2g2 * 2g)) = 0
(12 + -3g + -6g2 + (-8g + 2g2 + 4g3)) = 0

Reorder the terms:
(12 + -3g + -8g + -6g2 + 2g2 + 4g3) = 0

Combine like terms: -3g + -8g = -11g
(12 + -11g + -6g2 + 2g2 + 4g3) = 0

Combine like terms: -6g2 + 2g2 = -4g2
(12 + -11g + -4g2 + 4g3) = 0

Solving
12 + -11g + -4g2 + 4g3 = 0

Solving for variable 'g'.

The solution to this equation could not be determined.

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